Optimal. Leaf size=130 \[ -\frac {1}{5} \left (1-x^3\right )^{5/3}+\frac {1}{2} \left (1-x^3\right )^{2/3}+\frac {1}{2 \sqrt [3]{1-x^3}}+\frac {\log \left (x^3+1\right )}{12 \sqrt [3]{2}}-\frac {\log \left (\sqrt [3]{2}-\sqrt [3]{1-x^3}\right )}{4 \sqrt [3]{2}}-\frac {\tan ^{-1}\left (\frac {2^{2/3} \sqrt [3]{1-x^3}+1}{\sqrt {3}}\right )}{2 \sqrt [3]{2} \sqrt {3}} \]
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Rubi [A] time = 0.10, antiderivative size = 130, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.409, Rules used = {446, 87, 43, 783, 78, 55, 617, 204, 31} \[ -\frac {1}{5} \left (1-x^3\right )^{5/3}+\frac {1}{2} \left (1-x^3\right )^{2/3}+\frac {1}{2 \sqrt [3]{1-x^3}}+\frac {\log \left (x^3+1\right )}{12 \sqrt [3]{2}}-\frac {\log \left (\sqrt [3]{2}-\sqrt [3]{1-x^3}\right )}{4 \sqrt [3]{2}}-\frac {\tan ^{-1}\left (\frac {2^{2/3} \sqrt [3]{1-x^3}+1}{\sqrt {3}}\right )}{2 \sqrt [3]{2} \sqrt {3}} \]
Antiderivative was successfully verified.
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Rule 31
Rule 43
Rule 55
Rule 78
Rule 87
Rule 204
Rule 446
Rule 617
Rule 783
Rubi steps
\begin {align*} \int \frac {x^{11}}{\left (1-x^3\right )^{4/3} \left (1+x^3\right )} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {x^3}{(1-x)^{4/3} (1+x)} \, dx,x,x^3\right )\\ &=\frac {1}{3} \operatorname {Subst}\left (\int \left (-\frac {x}{\sqrt [3]{1-x}}-\frac {x}{\sqrt [3]{1-x} \left (-1+x^2\right )}\right ) \, dx,x,x^3\right )\\ &=-\left (\frac {1}{3} \operatorname {Subst}\left (\int \frac {x}{\sqrt [3]{1-x}} \, dx,x,x^3\right )\right )-\frac {1}{3} \operatorname {Subst}\left (\int \frac {x}{\sqrt [3]{1-x} \left (-1+x^2\right )} \, dx,x,x^3\right )\\ &=-\left (\frac {1}{3} \operatorname {Subst}\left (\int \left (\frac {1}{\sqrt [3]{1-x}}-(1-x)^{2/3}\right ) \, dx,x,x^3\right )\right )-\frac {1}{3} \operatorname {Subst}\left (\int \frac {x}{(-1-x) (1-x)^{4/3}} \, dx,x,x^3\right )\\ &=\frac {1}{2 \sqrt [3]{1-x^3}}+\frac {1}{2} \left (1-x^3\right )^{2/3}-\frac {1}{5} \left (1-x^3\right )^{5/3}+\frac {1}{6} \operatorname {Subst}\left (\int \frac {1}{(-1-x) \sqrt [3]{1-x}} \, dx,x,x^3\right )\\ &=\frac {1}{2 \sqrt [3]{1-x^3}}+\frac {1}{2} \left (1-x^3\right )^{2/3}-\frac {1}{5} \left (1-x^3\right )^{5/3}+\frac {\log \left (1+x^3\right )}{12 \sqrt [3]{2}}-\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{2^{2/3}+\sqrt [3]{2} x+x^2} \, dx,x,\sqrt [3]{1-x^3}\right )+\frac {\operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{2}-x} \, dx,x,\sqrt [3]{1-x^3}\right )}{4 \sqrt [3]{2}}\\ &=\frac {1}{2 \sqrt [3]{1-x^3}}+\frac {1}{2} \left (1-x^3\right )^{2/3}-\frac {1}{5} \left (1-x^3\right )^{5/3}+\frac {\log \left (1+x^3\right )}{12 \sqrt [3]{2}}-\frac {\log \left (\sqrt [3]{2}-\sqrt [3]{1-x^3}\right )}{4 \sqrt [3]{2}}+\frac {\operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+2^{2/3} \sqrt [3]{1-x^3}\right )}{2 \sqrt [3]{2}}\\ &=\frac {1}{2 \sqrt [3]{1-x^3}}+\frac {1}{2} \left (1-x^3\right )^{2/3}-\frac {1}{5} \left (1-x^3\right )^{5/3}-\frac {\tan ^{-1}\left (\frac {1+2^{2/3} \sqrt [3]{1-x^3}}{\sqrt {3}}\right )}{2 \sqrt [3]{2} \sqrt {3}}+\frac {\log \left (1+x^3\right )}{12 \sqrt [3]{2}}-\frac {\log \left (\sqrt [3]{2}-\sqrt [3]{1-x^3}\right )}{4 \sqrt [3]{2}}\\ \end {align*}
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Mathematica [C] time = 0.02, size = 48, normalized size = 0.37 \[ \frac {-5 \, _2F_1\left (-\frac {1}{3},1;\frac {2}{3};\frac {1}{2} \left (1-x^3\right )\right )-2 x^6-x^3+13}{10 \sqrt [3]{1-x^3}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.58, size = 159, normalized size = 1.22 \[ -\frac {10 \, \sqrt {6} 2^{\frac {1}{6}} \left (-1\right )^{\frac {1}{3}} {\left (x^{3} - 1\right )} \arctan \left (\frac {1}{6} \cdot 2^{\frac {1}{6}} {\left (2 \, \sqrt {6} \left (-1\right )^{\frac {1}{3}} {\left (-x^{3} + 1\right )}^{\frac {1}{3}} - \sqrt {6} 2^{\frac {1}{3}}\right )}\right ) + 5 \cdot 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{3} - 1\right )} \log \left (2^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} {\left (-x^{3} + 1\right )}^{\frac {1}{3}} - 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} + {\left (-x^{3} + 1\right )}^{\frac {2}{3}}\right ) - 10 \cdot 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{3} - 1\right )} \log \left (-2^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} + {\left (-x^{3} + 1\right )}^{\frac {1}{3}}\right ) - 12 \, {\left (2 \, x^{6} + x^{3} - 8\right )} {\left (-x^{3} + 1\right )}^{\frac {2}{3}}}{120 \, {\left (x^{3} - 1\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.18, size = 120, normalized size = 0.92 \[ -\frac {1}{12} \, \sqrt {3} 2^{\frac {2}{3}} \arctan \left (\frac {1}{6} \, \sqrt {3} 2^{\frac {2}{3}} {\left (2^{\frac {1}{3}} + 2 \, {\left (-x^{3} + 1\right )}^{\frac {1}{3}}\right )}\right ) - \frac {1}{5} \, {\left (-x^{3} + 1\right )}^{\frac {5}{3}} + \frac {1}{24} \cdot 2^{\frac {2}{3}} \log \left (2^{\frac {2}{3}} + 2^{\frac {1}{3}} {\left (-x^{3} + 1\right )}^{\frac {1}{3}} + {\left (-x^{3} + 1\right )}^{\frac {2}{3}}\right ) - \frac {1}{12} \cdot 2^{\frac {2}{3}} \log \left ({\left | -2^{\frac {1}{3}} + {\left (-x^{3} + 1\right )}^{\frac {1}{3}} \right |}\right ) + \frac {1}{2} \, {\left (-x^{3} + 1\right )}^{\frac {2}{3}} + \frac {1}{2 \, {\left (-x^{3} + 1\right )}^{\frac {1}{3}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 3.79, size = 497, normalized size = 3.82 \[ -\frac {\RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right ) \ln \left (\frac {72 x^{3} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right )^{2} \RootOf \left (\textit {\_Z}^{3}-4\right )^{2}+15 x^{3} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right ) \RootOf \left (\textit {\_Z}^{3}-4\right )^{3}+72 x^{3} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right )+15 x^{3} \RootOf \left (\textit {\_Z}^{3}-4\right )+126 \left (-x^{3}+1\right )^{\frac {1}{3}} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right ) \RootOf \left (\textit {\_Z}^{3}-4\right )-168 \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right )-35 \RootOf \left (\textit {\_Z}^{3}-4\right )+42 \left (-x^{3}+1\right )^{\frac {2}{3}}}{\left (x +1\right ) \left (x^{2}-x +1\right )}\right )}{2}-\frac {\RootOf \left (\textit {\_Z}^{3}-4\right ) \ln \left (\frac {-45 x^{3} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right )^{2} \RootOf \left (\textit {\_Z}^{3}-4\right )^{2}-6 x^{3} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right ) \RootOf \left (\textit {\_Z}^{3}-4\right )^{3}+15 x^{3} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right )+2 x^{3} \RootOf \left (\textit {\_Z}^{3}-4\right )+63 \left (-x^{3}+1\right )^{\frac {1}{3}} \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right ) \RootOf \left (\textit {\_Z}^{3}-4\right )-105 \RootOf \left (36 \textit {\_Z}^{2}+6 \textit {\_Z} \RootOf \left (\textit {\_Z}^{3}-4\right )+\RootOf \left (\textit {\_Z}^{3}-4\right )^{2}\right )-14 \RootOf \left (\textit {\_Z}^{3}-4\right )+21 \left (-x^{3}+1\right )^{\frac {2}{3}}}{\left (x +1\right ) \left (x^{2}-x +1\right )}\right )}{12}-\frac {2 x^{6}+x^{3}-8}{10 \left (-x^{3}+1\right )^{\frac {1}{3}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.27, size = 119, normalized size = 0.92 \[ -\frac {1}{12} \, \sqrt {3} 2^{\frac {2}{3}} \arctan \left (\frac {1}{6} \, \sqrt {3} 2^{\frac {2}{3}} {\left (2^{\frac {1}{3}} + 2 \, {\left (-x^{3} + 1\right )}^{\frac {1}{3}}\right )}\right ) - \frac {1}{5} \, {\left (-x^{3} + 1\right )}^{\frac {5}{3}} + \frac {1}{24} \cdot 2^{\frac {2}{3}} \log \left (2^{\frac {2}{3}} + 2^{\frac {1}{3}} {\left (-x^{3} + 1\right )}^{\frac {1}{3}} + {\left (-x^{3} + 1\right )}^{\frac {2}{3}}\right ) - \frac {1}{12} \cdot 2^{\frac {2}{3}} \log \left (-2^{\frac {1}{3}} + {\left (-x^{3} + 1\right )}^{\frac {1}{3}}\right ) + \frac {1}{2} \, {\left (-x^{3} + 1\right )}^{\frac {2}{3}} + \frac {1}{2 \, {\left (-x^{3} + 1\right )}^{\frac {1}{3}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.15, size = 139, normalized size = 1.07 \[ \frac {1}{2\,{\left (1-x^3\right )}^{1/3}}-\frac {2^{2/3}\,\ln \left (\frac {{\left (1-x^3\right )}^{1/3}}{4}-\frac {2^{1/3}}{4}\right )}{12}+\frac {{\left (1-x^3\right )}^{2/3}}{2}-\frac {{\left (1-x^3\right )}^{5/3}}{5}-\frac {2^{2/3}\,\ln \left (\frac {{\left (1-x^3\right )}^{1/3}}{4}-\frac {2^{1/3}\,{\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}^2}{16}\right )\,\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}{24}+\frac {2^{2/3}\,\ln \left (\frac {{\left (1-x^3\right )}^{1/3}}{4}-\frac {2^{1/3}\,{\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}^2}{16}\right )\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}{24} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{11}}{\left (- \left (x - 1\right ) \left (x^{2} + x + 1\right )\right )^{\frac {4}{3}} \left (x + 1\right ) \left (x^{2} - x + 1\right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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